document.write( "Question 1046238: A rectangle has a perimeter of 154 centimeters. If the length of the rectangle is 6 times its width, find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #661729 by addingup(3677) You can put this solution on YOUR website! Perimeter of the rectangle: \n" ); document.write( "2L+2W = 154 (1) \n" ); document.write( "and \n" ); document.write( "L = 6W Substitute in (1) \n" ); document.write( "2(6W)+2W = 154 \n" ); document.write( "12W+2W = 154 \n" ); document.write( "14W = 154 \n" ); document.write( "W = 11 So the width is 11 and the length 6(11)= 66 \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "Check: \n" ); document.write( "2(11)+2(66) = \n" ); document.write( "= 22+132 = 154 Correct \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " |