document.write( "Question 1046199: What amount of a 15% hcl acid solution must be mixed with a 20% hcl acid solution to obtain 50 milliliters of 18% solution? \n" ); document.write( "
Algebra.Com's Answer #661682 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the amount of 20% solution. Then: \n" ); document.write( ".2n+.15(50-n)=.18(50) \n" ); document.write( ".05n+7.5=9 \n" ); document.write( ".05n=1.5 \n" ); document.write( "n=30 \n" ); document.write( "You need 30ml of 20% solution, and 20ml of 15% solution to make 50ml of 18% solution. ☺☺☺☺ \n" ); document.write( " |