document.write( "Question 1046168: Hello, I'm new to these kind of questions so I have no idea where to start... The question is:
\n" ); document.write( "Tom bought a notebook with 100 sheets and numbered its pages consecutively from 1 to 200. Jerry pulled out 43 sheets and added up all 86 page numbers written on both sides of each of the sheets. Can the sum be equal to 2016?
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Algebra.Com's Answer #661671 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
First of all, you must realize that, for ANY sheet of the notebook,
\n" ); document.write( "the front sheet will always be numbered ODD (and so the back page will always
\n" ); document.write( "be numbered even.)\r
\n" ); document.write( "\n" ); document.write( "Thus, the number pages of the sheets will form a sequence that looks like this:\r
\n" ); document.write( "\n" ); document.write( "\"O%5B1%5D\", \"O%5B1%5D%2B1\", \"O%5B2%5D\", \"O%5B2%5D%2B1\", \"O%5B3%5D\", \"O%5B3%5D%2B1\",..., \"O%5B42%5D\", \"O%5B42%5D%2B1\", \"O%5B43%5D\", \"O%5B43%5D%2B1\",\r
\n" ); document.write( "\n" ); document.write( "where \"O%5Bk%5D\" denotes the odd number paging of the front page of the kth sheet.\r
\n" ); document.write( "\n" ); document.write( "Suppose we sum all of these pagings. The sum would be \r
\n" ); document.write( "\n" ); document.write( "\"sum%282%2AO%5Bk%5D%2C+k=1%2C43%29%2B43\".\r
\n" ); document.write( "\n" ); document.write( "Letting this equal 2016, we get\r
\n" ); document.write( "\n" ); document.write( "\"sum%282%2AO%5Bk%5D%2C+k=1%2C43%29%2B43+=+2016\".\r
\n" ); document.write( "\n" ); document.write( "===> \"2sum%28O%5Bk%5D%2C+k=1%2C43%29=+1973\".\r
\n" ); document.write( "\n" ); document.write( "Contradiction.\r
\n" ); document.write( "\n" ); document.write( "Therefore the sum CANNOT be 2016.\r
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