document.write( "Question 1046181: Ref. 1046146:\r
\n" ); document.write( "\n" ); document.write( "0.95 = 0.4v + 0.4\r
\n" ); document.write( "\n" ); document.write( "0.95 - 0.4 = 0.4v + 0.4 - 0.4\r
\n" ); document.write( "\n" ); document.write( "0.55 = 0.4v\r
\n" ); document.write( "\n" ); document.write( "0.55 / 0.4 = 0.4v / 0.4\r
\n" ); document.write( "\n" ); document.write( "1.375 = v\r
\n" ); document.write( "\n" ); document.write( "Where am I correct ?\r
\n" ); document.write( "\n" ); document.write( "Also, I have read that if, an amount of water, in this case, the amt. of alcohol is diluted, but when alcohol is added, the amt. remains unchanged. Am I on the right track ?\r
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Algebra.Com's Answer #661670 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
0.55 = 0.4v\r
\n" ); document.write( "\n" ); document.write( "0.55 / 0.4 = 0.4v / 0.4\r
\n" ); document.write( "\n" ); document.write( "1.375 = v\r
\n" ); document.write( "\n" ); document.write( "Where am I correct ?\r
\n" ); document.write( "\n" ); document.write( "Also, I have read that if, an amount of water, in this case, the amt. of alcohol is diluted, but when alcohol is added, the amt. remains unchanged. Am I on the right track ?
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\n" ); document.write( "\n" ); document.write( "A 1 qt. mixture of alcohol and water is 95% alcohol. The mixture is to be reduced to 40% alcohol. Determine amount of distilled water to be added.
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\n" ); document.write( "Add W quarts of water
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\n" ); document.write( "1*95 + W*0 = (1 + W)* 40
\n" ); document.write( "40W + 40 = 95
\n" ); document.write( "40W = 55
\n" ); document.write( "W = 11/8 quarts
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