document.write( "Question 1046164: Corey is 138 miles away from Paul. They are traveling towards each other. If Paul travels 7 mph faster than Corey and they meet after 6 hours, how fast was each traveling?
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Algebra.Com's Answer #661654 by ikleyn(52780)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Corey is 138 miles away from Paul. They are traveling towards each other. If Paul travels 7 mph faster than Corey and they meet after 6 hours, how fast was each traveling? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let x = Corey's speed in mph. Then Paul's speed is (x+7) mph. \r\n" ); document.write( "\r\n" ); document.write( "Then you have the \"distance\" equation\r\n" ); document.write( "\r\n" ); document.write( "6x + 6(x+7) = 138.\r\n" ); document.write( "\r\n" ); document.write( "Solve it for x.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |