document.write( "Question 1046146: Ref. Question 1046126:\r
\n" ); document.write( "\n" ); document.write( ".95(1) = .40(x + 1)\r
\n" ); document.write( "\n" ); document.write( ".95 = .40x + 40\r
\n" ); document.write( "\n" ); document.write( ".95 - 40 = .40x + 40 - 40\r
\n" ); document.write( "\n" ); document.write( ".55 = .40x\r
\n" ); document.write( "\n" ); document.write( ".55 / .40 = .40x / .40 \r
\n" ); document.write( "\n" ); document.write( "1.375 = x\r
\n" ); document.write( "\n" ); document.write( "Where am I correct ?
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Algebra.Com's Answer #661646 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
A 1 qt. mixture of alcohol and water is 95% alcohol. The mixture is to be reduced to 40% alcohol. Determine amount of distilled water to be added. \r
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\n" ); document.write( "\n" ); document.write( "A clear way to think of it is \"%28amountAlcohol%29%2F%28amountMixturePlusamountAddWater%29=ConcentrationAlcoholDesired\";
\n" ); document.write( "and your variable will be amountAddWater or amount of water to add to the mixture.\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2A0.95%29%2F%281%2Bv%29=0.4\", which is written using decimal fractions instead of percents. The amount of water to add is assigned as v.\r
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\n" ); document.write( "\n" ); document.write( "SOLVE this equation for v.\r
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\n" ); document.write( "There is a decimal mistake in the steps you asked about. Stepping through mine just two ,\r
\n" ); document.write( "\n" ); document.write( "\"0.95%2F%28v%2B1%29=0.4\"\r
\n" ); document.write( "\n" ); document.write( "\"0.95=0.4%28v%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"0.95=0.4v%2B0.4\"
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