document.write( "Question 1046124: A function y=ax^2-4x-c. If the y-int is -3 and the co-ordinates of the vertex is (2,-7), find the value of a.\r
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Algebra.Com's Answer #661619 by Boreal(15235)\"\" \"About 
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ax^2-4x-c
\n" ); document.write( "Vertex is (h,k) where h=2 and k=-7
\n" ); document.write( "This is a(x-h)^2+k
\n" ); document.write( "a(x-2)^2-7 is the function, and when x=0, y=-3 (y-intercept)
\n" ); document.write( "Therefore a(-2)^2-7= -3
\n" ); document.write( "4a-7=-3
\n" ); document.write( "4a=4
\n" ); document.write( "a=1 ANSWER
\n" ); document.write( "Therefore, the function should be (x-2)^2-7 in vertex form or
\n" ); document.write( "x^2-4x-3 in standard form.
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cx%5E2-4x-3%29\"
\n" ); document.write( "Another way to check this or to do it is the vertex x component is -b/2a.
\n" ); document.write( "We know the vertex is -(-4)/2a=2 (the 2 is given)
\n" ); document.write( "4/2a=2
\n" ); document.write( "4=4a
\n" ); document.write( "a=1
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