document.write( "Question 1046112: Leah went to the internet cafe traveling 20 mph and returned home traveling 10 mph. If the total trip took 6 hours, how long did Leah travel at each speed?
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Algebra.Com's Answer #661615 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+t+\" = time in hrs going TO the cafe
\n" ); document.write( "\"+6+-+t+\" = time in hrs returning FROM cafe
\n" ); document.write( "Let \"+d+\" = the one-way distance to cafe
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\n" ); document.write( "Going to cafe:
\n" ); document.write( "(1) \"+d+=+20t+\"
\n" ); document.write( "Returning from cafe:
\n" ); document.write( "(2) \"+d+=+10%2A%28+6-t+%29+\"
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\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+20t+=+10%2A%28+6-t+%29+\"
\n" ); document.write( "(2) \"+20t+=+60+-+10t+\"
\n" ); document.write( "(2) \"+30t+=+60+\"
\n" ); document.write( "(2) \"+t+=+2+\" hrs
\n" ); document.write( "and
\n" ); document.write( "\"+6+-+t+=+6+-+2+\"
\n" ); document.write( "\"+6+-+t+=+4+\" hrs
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\n" ); document.write( "Leah took 2 hrs going 20 mi/hr
\n" ); document.write( "Leah took 4 hrs going 10 mi/hr
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\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+20t+\"
\n" ); document.write( "(1) \"+d+=+20%2A2+\"
\n" ); document.write( "(1) \"+d+=+40+\" mi
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+10%2A%28+6-t+%29+\"
\n" ); document.write( "(2) \"+d+=+10%2A%28+6-2+%29+\"
\n" ); document.write( "(2) \"+d+=+10%2A4+\"
\n" ); document.write( "(2) \"+d+=+40+\" mi
\n" ); document.write( "OK
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