document.write( "Question 1046068: There are two alloys P and Q made up of silver, copper and aluminium. Alloy P contains 45% silver and rest aluminum. Alloy Q contains 30% silver, 35% copper and rest aluminium. Alloys P and Q are mixed in the ratio of 1 : 4.5. The approximate percentages of silver and copper in the newly formed alloy is \n" ); document.write( "
Algebra.Com's Answer #661612 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
No units of measure are given, so I could say
\n" ); document.write( "P and Q have units of ounces, grams, or whatever.
\n" ); document.write( "I could even make up units
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\n" ); document.write( "I'll say there are \"+100+\" ounces of \"+P+\" so there
\n" ); document.write( "must be \"+450+\" ounces of Q
\n" ); document.write( "( this is a ratio of 1:4.5 )
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\n" ); document.write( "For P:
\n" ); document.write( "\"+.45%2A100+=+45+\" ounces silver
\n" ); document.write( "\"+.55%2A100+=+55+\" ounces aluminum
\n" ); document.write( "For Q:
\n" ); document.write( "\"+.3%2A450+=+135+\" ounces silver
\n" ); document.write( "\"+.35%2A450+=+157.5+\" ounces copper
\n" ); document.write( "\"+.35%2A450+=+157.5+\" ounces aluminum
\n" ); document.write( "-------------------------------------
\n" ); document.write( "\"+45+%2B+135+=+180+\" ounces silver
\n" ); document.write( "\"+55+%2B+157.5+=+212.5+\" ounces aluminum
\n" ); document.write( "\"+157.5+\" ounces copper
\n" ); document.write( "---------------------------------------
\n" ); document.write( "The total weight of P + Q is
\n" ); document.write( "\"+100+%2B+450+=+550+\" ounces
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\n" ); document.write( "For silver:
\n" ); document.write( "\"+180%2F550+=+.3273+\"
\n" ); document.write( "33% silver
\n" ); document.write( "For copper:
\n" ); document.write( "\"+157.5%2F550+=+.2864+\"
\n" ); document.write( "29% copper
\n" ); document.write( "----------------------
\n" ); document.write( "check answers:
\n" ); document.write( "\"+1+-+%28+.33+%2B+.29+%29+=+1+-+.62+\"
\n" ); document.write( "\"+1+-+.62+=+.38+\"
\n" ); document.write( "For aluminum:
\n" ); document.write( "\"+212.5%2F550+=+.3864+\"
\n" ); document.write( "39%
\n" ); document.write( "this looks close enough
\n" ); document.write( "Hop I got it!\r
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