document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91126>Question 91126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Add<BR>\n" );
document.write( "1/4+ 3/10+ 4/15\r<BR>\n" );
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document.write( "Divide by moving the decimal point. 27.3 divided by 10 (to the power of 5)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66151 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/4+3/10+4/15 now find a common denominator.<BR>\n" );
document.write( "4=2*2<BR>\n" );
document.write( "10=2*5<BR>\n" );
document.write( "15=3*5<BR>\n" );
document.write( "the 2 & 5 are common to two of the numbers therefore we use them only once & multiply these two 3*3 to the other factors 2*3.<BR>\n" );
document.write( "thus we have the LCD of 2*5*2*3=60<BR>\n" );
document.write( "(1*15+3*6+4*4)/60<BR>\n" );
document.write( "(15+36+16)/60<BR>\n" );
document.write( "67/60 answer.<BR>\n" );
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document.write( "27.3/10^5<BR>\n" );
document.write( "27.3*10^(-5)<BR>\n" );
document.write( ".000273 answer.<BR>\n" );
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