document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045998>Question 1045998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the triangle  has 6m,8m and 10m .what is the angel formen by the intersection  of the two shortest sides?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #661497 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=661497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The smallest two sides are 6 m and 8 m. The angle between them is opposite the side 10 m.\r<BR>\n" );
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document.write( "Law of Cosines\r<BR>\n" );
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document.write( "c^2 = a^2 + b^2 - 2*a*b*cos(C)\r<BR>\n" );
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document.write( "10^2 = 6^2 + 8^2 - 2*6*8*cos(C)\r<BR>\n" );
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document.write( "100 = 36 + 64 - 96*cos(C)\r<BR>\n" );
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document.write( "100 = 100 - 96*cos(C)\r<BR>\n" );
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document.write( "100 - 100 = 100 - 96*cos(C) - 100\r<BR>\n" );
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document.write( "0 = -96*cos(C)\r<BR>\n" );
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document.write( "-96*cos(C) = 0\r<BR>\n" );
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document.write( "cos(C) = 0\r<BR>\n" );
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document.write( "C = 90 degrees\r<BR>\n" );
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document.write( "The final answer is 90 degrees.  </SPAN>\n" );
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