document.write( "Question 91137: Factoring a quadratic with leading coefficient greater than one-- can your calculators answer these problems, so far answers are all wrong
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document.write( "10w^2+11w-6 \n" );
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Algebra.Com's Answer #66149 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 10W^2+11W-6 \n" ); document.write( "FACTORS OF 10 ARE 10&1, -10&-1, 5&2, -5&-2 \n" ); document.write( "FACTORS OF -6 ARE -1&6, 1&-6, -2&3, 2&-3 \n" ); document.write( "NOW WE NEED TO PICK A PAIR OF X + Y FACTORS THAT WNEM MULTIPLIED ADD UP TO 11 \n" ); document.write( "(10*-1)+(-1*-6)=-10+6=4 NOT A GOOD PICK. \n" ); document.write( "(5*-2)+(2+3)=-10+6=-4 NOT A GOOOD PICK. \n" ); document.write( "(5*3)+(2*-2)=15-4=11 LOOKS LIKE A GOOD PICK. THUS THE FACTORS ARE: \n" ); document.write( "(5W-2)(2W+3) ANSWER. \n" ); document.write( " |