document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045928>Question 1045928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> iam not understanding the question and in fact i have no idea how to solve it! plz help \r<BR>\n" );
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document.write( "let f(x)={ (x+2p if x<-2) }<BR>\n" );
document.write( "         { (3px+q if x -2<=x<=1) }<BR>\n" );
document.write( "         { (3x-2q if x>1) }\r<BR>\n" );
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document.write( "determine the values of p and q that make f continuous </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #661456 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=661456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to be continuous..need to look at when x = -2 and x-1<BR>\n" );
document.write( "when x = -2<BR>\n" );
document.write( "x + 2p = 3px + q<BR>\n" );
document.write( "Substitute x = -2<BR>\n" );
document.write( "-2 + 2p = -6p + q<BR>\n" );
document.write( "-2 = -8p + q  ****<BR>\n" );
document.write( "when x = 1<BR>\n" );
document.write( "3px + q = 3x - 2q<BR>\n" );
document.write( "Substitute x = 1<BR>\n" );
document.write( "3p + q = 3 - 2q<BR>\n" );
document.write( "3p + 3q = 3  ***<BR>\n" );
document.write( "____________________<BR>\n" );
document.write( "-8p + q = -2<BR>\n" );
document.write( "3p  +3q  = 3<BR>\n" );
document.write( "__________________ Multiplying 1st by -3 to eliminate q when adding both<BR>\n" );
document.write( "27p = 9<BR>\n" );
document.write( "p = 1/3<BR>\n" );
document.write( "q = 2/3 <BR>\n" );
document.write( " </SPAN>\n" );
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