document.write( "Question 1045941: find the standard equation of the line which passes through (1,-3) and is perpendicular to the line defined by 2y=3x-1 \n" ); document.write( "
Algebra.Com's Answer #661452 by ewatrrr(24785)\"\" \"About 
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2y=3x-1
\n" ); document.write( "finding the Slope
\n" ); document.write( "the standard slope-intercept form for an equation of a line is \"y+=+highlight_green%28m%29x+%2B+highlight%28b%29\"
\n" ); document.write( "where m is the slope and b the y-intercept.
\n" ); document.write( "2y=3x-1
\n" ); document.write( "Solving for y
\n" ); document.write( "y =-(3/2)x +1/2 Green Line
\n" ); document.write( "m = -3/2
\n" ); document.write( "Slope of Line perpendicular is 2/3 (negative reciprocal)
\n" ); document.write( "***Using point-slope form, \"y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29\"
\n" ); document.write( "y +3 = (2/3)( x - 1) Pt (1,-3) on this perpendicular line
\n" ); document.write( "y = (2/3)x -2/3 - 9/3
\n" ); document.write( "y = (2/3)x - 11/3 Blue Line
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