document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045944>Question 1045944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you bought a car for $10,000 four years ago, since then it has lost 20% of its original value. Assuming depreciation is linear, how many years after your initial purchase will it be when the car is only worth $1,000? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #661447 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=661447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  bought a car for $10,000 <BR>\n" );
document.write( "four years lost 20% ($2000) | Depreciated $500 per year<BR>\n" );
document.write( "Let x represent the number of years...<BR>\n" );
document.write( "Depreciate Value = 10000 - 500x\r<BR>\n" );
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document.write( "when the car is only worth $1,000?<BR>\n" );
document.write( "1000 = 10000 - 500x<BR>\n" );
document.write( "500x = 10000-1000<BR>\n" );
document.write( "500x = 9000<BR>\n" );
document.write( "x = 9000/500<BR>\n" );
document.write( "x = 18 years, when the car is only worth $1,000 </SPAN>\n" );
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