document.write( "Question 1045870: A function $f$ has horizontal asymptote of $y = -4,$ a vertical asymptote of $x = 3,$ and an $x$-intercept at $(1,0).$
\n" ); document.write( "Part (b): Let $f$ be of the form
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Algebra.Com's Answer #661408 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Igor's input box doesn't understand TeX or LaTeX. Your dollar signs just make your input difficult to read. Use standard plain text notation when posting here, please. See Formatting Math as Text for more information about how to communicate math expressions in plain text that everyone understands.\r
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\n" ); document.write( "\n" ); document.write( "If there is a horizontal asymptote, then the degree of the numerator and denominator polynomials must be equal (which is true in this case) and the equation of the asymptote must be where is the lead coefficient of the numerator polynomial and is the lead coefficient of the denominator polynomial.\r
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\n" ); document.write( "\n" ); document.write( "So if your function is:\r
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\n" ); document.write( "\n" ); document.write( "and if the equation of the horizontal asymptote is\r
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\n" ); document.write( "\n" ); document.write( "A vertical asymptote exists where the denominator polynomial is equal to zero, so if the vertical asymptote is\r
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\n" ); document.write( "\n" ); document.write( "which is to say\r
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\n" ); document.write( "\n" ); document.write( "In order for the function value to be zero, the numerator must be zero. So, given an x-intercept of \r
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\n" ); document.write( "\n" ); document.write( "Putting it all together,\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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