document.write( "Question 1045888: Mariana averaged 83 on her first three history exams. The first score was 93. The second score was 44 less than the third score. What did she score on the second and third exams? \n" ); document.write( "
Algebra.Com's Answer #661400 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mariana averaged 83 on her first three history exams. \n" ); document.write( " The first score was 93. \n" ); document.write( "The second score was 44 less than the third score. \n" ); document.write( " What did she score on the second and third exams? \n" ); document.write( ": \n" ); document.write( "let x = the score on the 3rd exam \n" ); document.write( "then \n" ); document.write( "(x-44) = the score on the 2nd \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply both sides by 3, combine like terms \n" ); document.write( "93 - 44 + x + x = 3(83) \n" ); document.write( "49 + 2x = 249 \n" ); document.write( "2x = 249 - 49 \n" ); document.write( "2x = 200 \n" ); document.write( "x = 100 her score on the 3rd exam \n" ); document.write( "then \n" ); document.write( "100 - 44 = 56 on the 2nd exam \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check \n" ); document.write( " |