document.write( "Question 91133: Solve for the unknown: 8/52 = m/39
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\n" ); document.write( "Is the rate 1.2 inches of rain/5hours equivalent to the rate 2.1 inches of rain/8hours?
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Algebra.Com's Answer #66140 by stanbon(75887)\"\" \"About 
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Solve for the unknown: 8/52 = m/39
\n" ); document.write( "Multiply both sides by 39 to get:
\n" ); document.write( "m= 39(8/52) = 13(8/14)= 13(4/7) = 52/7
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\n" ); document.write( "Is the rate 1.2 inches of rain/5hours equivalent to the rate 2.1 inches of rain/8hours?
\n" ); document.write( "1.2/5 ? 2.1/8
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\n" ); document.write( "To get the 8 in the denominator multiply numerator and denominator
\n" ); document.write( "by (8/5).
\n" ); document.write( "You would get [(1.2*(8/5))]/[5*(8/5)) = 1.92/8
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\n" ); document.write( "So, they are not equivalent.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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