document.write( "Question 91117: This one's like the other, but a bit different. 3(x-2)^2+1=0 I could tell I need to use the sqare root property but when I look in my textbook for an explanation, I don't undestand the + - in figuring it out.\r
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Algebra.Com's Answer #66137 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"3%28x-2%29%5E2%2B1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3%28x-2%29%5E2=-1\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2=-1%2F3\" Divide both sides by 3\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0%2B-sqrt%28-1%2F3%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0%2B-i%2Asqrt%281%2F3%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2B-i%2Asqrt%281%2F3%29\" Add 2 to both sides
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