document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045835>Question 1045835</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 inches less than 3 times the width and the perimeter is 32. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #661346 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=661346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter(P)=2*Length(L) +2*Width(W) or P=2L+2W<BR>\n" );
document.write( "Let W=width<BR>\n" );
document.write( "Then Length=3W-4<BR>\n" );
document.write( "Soooo<BR>\n" );
document.write( "32=2(3W-4)+2W simplify<BR>\n" );
document.write( "32=6W-8+2W collect like terms and add 8 to each side<BR>\n" );
document.write( "32+8=8W<BR>\n" );
document.write( "8W=40<BR>\n" );
document.write( "W=5<BR>\n" );
document.write( "Length=3*5-4=11<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "2*11+2*5=32\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps--ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );