document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045817>Question 1045817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that during a test drive of two&#8203; cars, one car travels 135 miles in the same time that the second car travels 100 miles. If the speed of one car is 14 miles per hour faster than the speed of the second&#8203; car, find the speed of both cars.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #661331 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=661331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r be the rate of the slower car. Then:<BR>\n" );
document.write( "100/r=135/(r+14)<BR>\n" );
document.write( "135r=100r+1400<BR>\n" );
document.write( "35r=1400<BR>\n" );
document.write( "r=40 <BR>\n" );
document.write( "The slower car goes 40 mph; the faster one goes 54 mph. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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