document.write( "Question 1045812: CALCULUS(MAXIMA AND MINIMA):THE VOLUME OF A SPHERE IS INCREASING AT THE RATE OF 6CM^2/HR.AT WHAT RATE IS ITS SURFACE AREA INCREASING WHEN THE RADIUS IS 40 CM? \n" ); document.write( "

Algebra.Com's Answer #661323 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Related rates:
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document.write( "V = (4/3)pir^3
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document.write( "dV/dt = (4/3)pi 2r^2 dr/dt
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document.write( "6 =(4/3)pi* 2r^2 dr/dt
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document.write( "3/(4/3)pir^2 = dr/dt
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document.write( "= dr/dt
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document.write( "S = 4pir^2
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document.write( "dS/dt = 4pi 2r dr/dt  substitute for dr/dt to solve
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document.write( "dS/dt =
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document.write( "dS/dt = 18/r
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document.write( "substitute: r = 40cm \n" );
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