document.write( "Question 13169: There are bolts and nuts in a box. The number of bolts are 66 times as many as nuts \"B+=+66N\". If 20 more nuts are put in the box, there will be only 36 times as many bolts as nuts \"B+=+36%28N+%2B+20%29\". How many bolts are in the box? \n" ); document.write( "
Algebra.Com's Answer #6613 by akmb1215(68)\"\" \"About 
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You need to first assign variables for the nuts and bolts. I am going to use N for nuts and B for bolts.\r
\n" ); document.write( "\n" ); document.write( "I have added equations to your question to describe the sentences.\r
\n" ); document.write( "\n" ); document.write( "Since you know that B = 66N, and you also know that B = 36(N + 20), you can set these two equations equal to one another. Therefore, you get \"66N+=+36%28N+%2B+20%29\".\r
\n" ); document.write( "\n" ); document.write( "To solve this, use the distributive property to distribute the 36 across the N+20 to get \"66N+=+36N+%2B+720\". Move 36N to the left side of the equation by subtracting it from both sides of the equation to get \"30N+=+720\". Solve by dividing by 30. N=24.\r
\n" ); document.write( "\n" ); document.write( "To solve for B, plug in N=24 to the first original equation and solve. \"B+=+66%2824%29\"; B = 1,584
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