document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91104>Question 91104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question is to draw the line graph which represents d is greater/equal to -3.\r<BR>\n" );
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document.write( "Thank You, \r<BR>\n" );
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document.write( "KC </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66127 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start with the given inequality:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%3E=-3 ALIGN=MIDDLE  ALT=\"d%3E=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Set up a number line:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=number_line%28+500%2C+-10%2C+10%29 ALIGN=MIDDLE  ALT=\"number_line%28+500%2C+-10%2C+10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > note: just replace the x with the variable you are working with\r<BR>\n" );
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document.write( "Now plot the point -3 on the number line\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=number_line%28+500%2C+-10%2C+10%2C+-3%29 ALIGN=MIDDLE  ALT=\"number_line%28+500%2C+-10%2C+10%2C+-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now pick any test point you want, I'm going to choose 0, and test the inequality <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%3E=-3 ALIGN=MIDDLE  ALT=\"d%3E=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0%3E=-3 ALIGN=MIDDLE  ALT=\"0%3E=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=0 ALIGN=MIDDLE  ALT=\"d=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Since this inequality is  true, we simply shade the entire portion that contains 0 using the point -3 as the boundary. This means we shade everything to the right of the point -3 like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28500%2C50%2C-10%2C10%2C-10%2C10%2C%0D%0Anumber_line%28+500%2C+-10%2C+10%2C+-3%29%2C%0D%0Ablue%28line%28-3%2C-5%2C3%2B6.8%2C-5%29%29%2C%0D%0Ablue%28line%28-3%2C-6%2C3%2B6.8%2C-6%29%29%2C%0D%0Ablue%28line%28-3%2C-7%2C3%2B6.8%2C-7%29%29%2C%0D%0Ablue%28arrow%28-3%2C-5%2C3%2B7%2C-5%29%29%2C%0D%0Ablue%28arrow%28-3%2C-5.5%2C3%2B7%2C-5.5%29%29%2C%0D%0Ablue%28arrow%28-3%2C-6%2C3%2B7%2C-6%29%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > Graph of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%3E=-3 ALIGN=MIDDLE  ALT=\"d%3E=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > with the shaded region in blue\r<BR>\n" );
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document.write( "note: at the point -3, there is an <b>closed</b> circle. This means the point -3 is included from the solution set.\r<BR>\n" );
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