document.write( "Question 1045763: Susan averaged 91 mph on the way to Phoenix on the way home she average 78 mph and it took her an hour longer to drive home than it did for her to drive to Phoenix what is the total driving time fr Susan averaged 91 mph on the way to Phoenix on the way home she average 78 mph and it took her an hour longer to drive home than it did for her to drive to Phoenix what is the total driving time for Susan's trip? How far did Susan live from Phoenix ? \n" ); document.write( "
Algebra.Com's Answer #661247 by josgarithmetic(39623)\"\" \"About 
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Susan averaged 91 mph on the way to Phoenix. On the way home, she average 78 mph and it took her an hour longer to drive home than it did for her to drive to Phoenix. what is the total driving time? fr Susan averaged 91 mph on the way to Phoenix on the way home she average 78 mph and it took her an hour longer to drive home than it did for her to drive to Phoenix what is the total driving time for Susan's trip? How far did Susan live from Phoenix ?\r
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document.write( "               SPEED            TIME          DISTANCE\r\n" );
document.write( "GOING           91              t             d\r\n" );
document.write( "RETURN          78              t+1           d\r\n" );
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\n" ); document.write( "\n" ); document.write( "Observe the same distance d for \"going\" and \"return\".
\n" ); document.write( "\"91t=78%28t%2B1%29\"
\n" ); document.write( "Solve this for t, and then evaluate d using \"91%2At=d\".
\n" ); document.write( "Basic Travel Rate rule for constant rate R is RT=D, to relate time and distance.
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