document.write( "Question 1045749: Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the battery is twice the voltage at the second and one third the voltage of the third battery. Find the actual voltage of each battery. \n" ); document.write( "
Algebra.Com's Answer #661238 by josmiceli(19441)\"\" \"About 
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Let \"+V+\" = the voltage of the 2nd battery
\n" ); document.write( "\"+2V+\" = the voltage of the 1st battery
\n" ); document.write( "Let \"+V%5B3%5D+\" = the voltage of the 3rd battery
\n" ); document.write( "\"+2V+=+%281%2F3%29%2AV%5B3%5D+\"
\n" ); document.write( "\"+V%5B3%5D+=+6V+\"
\n" ); document.write( "------------------
\n" ); document.write( "\"+2V+%2B+V+%2B+6V+=+54+\"
\n" ); document.write( "\"+9V+=+54+\"
\n" ); document.write( "\"+V+=+6+\"
\n" ); document.write( "and
\n" ); document.write( "\"+2V+=+12+\"
\n" ); document.write( "\"+6V+=+36+\"
\n" ); document.write( "---------------
\n" ); document.write( "The battey voltages are:
\n" ); document.write( "12V , 6V , 36V
\n" ); document.write( "----------------
\n" ); document.write( "check answer:
\n" ); document.write( "\"+2V+%2B+V+%2B+6V+=+54+\"
\n" ); document.write( "\"+12+%2B+6+%2B+36+=+54+\"
\n" ); document.write( "\"+54+=+54+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );