Algebra.Com's Answer #661224 by MathTherapy(10552)  You can put this solution on YOUR website! Max has a small jar of coins containing pennies, nickels, and dimes. The total number of coins is 44 and the value of the coins is $2.20. If the number of dimes is twice the number of nickels, how many of each type of coin does Max have? \n" );
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document.write( "Let number of pennies, nickels, and dimes be P, N, and D, respectively \n" );
document.write( "Then we get: P + N + D = 44 ------- eq (i) \n" );
document.write( "Also, .01P + .05N + .1D = 2.2 ----- eq (ii) \n" );
document.write( "And, D = 2N ------ eq (iii)\r \n" );
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document.write( "P + N + 2N = 44 ------- Substituting 2N for D in eq (i) \n" );
document.write( "P + 3N = 44______P = 44 - 3N ------- eq (iv)\r \n" );
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document.write( ".01P + .05N + .1(2N) = 2.2 ------- Substituting 2N for D in eq (ii) \n" );
document.write( ".01P + .05N + .2N = 2.2 \n" );
document.write( ".01P + .25N = 2.2 ------ eq (v)\r \n" );
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document.write( ".01(44 - 3N) + .25N = 2.2 ------- Substituting 44 - 3N for P in eq (v) \n" );
document.write( ".44 - .03N + .25N = 2.2 \n" );
document.write( ".44 + .22N = 2.2 \n" );
document.write( ".22N = 2.2 - .44 \n" );
document.write( ".22N = 1.76 \n" );
document.write( "N, or \r \n" );
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document.write( "D = 2(8) ------- Substituting 8 for N in eq (iii) \n" );
document.write( "D, or \r \n" );
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document.write( "P = 44 - 3(8) -------- Substituting 8 for N in eq (iv) \n" );
document.write( "P, or \n" );
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