document.write( "Question 90868: Show the steps that you would take to solve the following algebraically:\r
\n" ); document.write( "\n" ); document.write( "A) 5-2/x-6=10-2x/x-6\r
\n" ); document.write( "\n" ); document.write( "B) What potential solution did you obtain? Explain why this is not a solution.
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Algebra.Com's Answer #66122 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Show the steps that you would take to solve the following algebraically:
\n" ); document.write( "A) 5-2/x-6=10-2x/x-6
\n" ); document.write( "Assume you mean (a couple sets of brackets would help)
\n" ); document.write( "\"5+-+%282%2F%28%28x-6%29%29%29\" = \"%28%2810+-+2x%29%29%2F%28%28x-6%29%29%29\"
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\n" ); document.write( "multiply both sides by (x-6) to get rid of the denominators, resulting in:
\n" ); document.write( "5(x-6) - 2 = 10 - 2x
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\n" ); document.write( "5x - 30 - 2 = 10x - 2x
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\n" ); document.write( "5x - 32 = 10 - 2x
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\n" ); document.write( "5x + 2x = 10 + 32
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\n" ); document.write( "7x = 42
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\n" ); document.write( "x = 42/7
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\n" ); document.write( "x = 6
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\n" ); document.write( "B) What potential solution did you obtain? x = 6
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\n" ); document.write( "Explain why this is not a solution.
\n" ); document.write( "When you substitute 6 for x in the denominators, you have division by 0.
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