document.write( "Question 1045648: Find the solution set of:
\n" ); document.write( "y=1/3(x-3)^2 - 3
\n" ); document.write( "(x-3)^2 + (y+2)^2 = 1
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Algebra.Com's Answer #661151 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"y=%281%2F3%29%28x-3%29%5E2+-+3\"
\n" ); document.write( "\"%28x-3%29%5E2+%2B+%28y%2B2%29%5E2+=+1\"
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F3%29%28x-3%29%5E2+-+3\" if you set \"x=0\", then \"y=+-+3\"........substitute it in \"%28x-3%29%5E2+%2B+%28y%2B2%29%5E2+=+1\" \r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2+%2B+%28-3%2B2%29%5E2+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2+%2B+%28-1%29%5E2+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2+%2B+1=+1\" \r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2+=+1+-1\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2+=+0\" it will be true if\r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29=+0\" and it will be true if \"x=3\"\r
\n" ); document.write( "\n" ); document.write( "so, real solution to the system above is: \"x=3\", \"y=-3\"\r
\n" ); document.write( "\n" ); document.write( "or point (\"3\",\"-3\")\r
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