document.write( "Question 1045647: X-y=9;x-y+3z=2;4y-3z=5 \n" ); document.write( "

Algebra.Com's Answer #661140 by ikleyn(52864) $\"\"$ $\"About$

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document.write( "x -  y      = 9,   (1)\r\n" );
document.write( "x -  y + 3z = 2,   (2)\r\n" );
document.write( "    4y - 3z = 5.   (3).\r\n" );
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document.write( "Distract the eq.(1) from the eq.(2).  You will get \r\n" );
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document.write( "3z = 2-9 = -7  --->  z = .\r\n" );
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document.write( "Then from (3), 4y = 5 + 3z =  = 5-7 = -2  --->  y =  = .\r\n" );
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document.write( "Then from (1), x = 9 + y =  = .\r\n" );
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document.write( "Answer. x = ,  y = ,  z = .\r\n" );
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