document.write( "Question 1045659: Determine the axis of parabola x^2-2x+8y+25=0. \n" ); document.write( "
Algebra.Com's Answer #661139 by ewatrrr(24785) You can put this solution on YOUR website! parabola x^2-2x+8y+25=0 \n" ); document.write( "8y = x^2-2x+25 \n" ); document.write( "completing the square on the left side of the EQ \n" ); document.write( "8y = (x-1)^2 -1 + 25 \n" ); document.write( "8y = (x-1)^2 + 24 \n" ); document.write( "y = (1/8)(x-1)^2 + 3 Vertex(1,3) \n" ); document.write( "Axis: x= 1 \n" ); document.write( " \n" ); document.write( "Need to Know____________ \n" ); document.write( "The vertex form of a Parabola opening up(a>0) or down(a<0), \n" ); document.write( " \n" ); document.write( "where(h,k) is the vertex and x = h is the Line of Symmetry , \n" ); document.write( "the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p) \n" ); document.write( " \n" ); document.write( " |