document.write( "Question 1045659: Determine the axis of parabola x^2-2x+8y+25=0. \n" ); document.write( "
Algebra.Com's Answer #661139 by ewatrrr(24785)\"\" \"About 
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parabola x^2-2x+8y+25=0
\n" ); document.write( "8y = x^2-2x+25
\n" ); document.write( "completing the square on the left side of the EQ
\n" ); document.write( "8y = (x-1)^2 -1 + 25
\n" ); document.write( "8y = (x-1)^2 + 24
\n" ); document.write( "y = (1/8)(x-1)^2 + 3 Vertex(1,3)
\n" ); document.write( "Axis: x= 1
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\n" ); document.write( "Need to Know____________
\n" ); document.write( "The vertex form of a Parabola opening up(a>0) or down(a<0),
\n" ); document.write( "\"y=a%28x-h%29%5E2+%2Bk\"
\n" ); document.write( "where(h,k) is the vertex and x = h is the Line of Symmetry ,
\n" ); document.write( "the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
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