document.write( "Question 1045649: suppose the length of a rectangle is 2x + 1 and the width is 3x-2 . find the value of x if the perimeter is equal to 38 inches\r
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Algebra.Com's Answer #661135 by ikleyn(52803) $\"\"$ $\"About$

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\n" ); document.write( "suppose the length of a rectangle is 2x + 1 and the width is 3x-2 . find the value of x if the perimeter is equal to 38 inches
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document.write( "2L + 2W = 38, or\r\n" );
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document.write( "2*(2x+1) + 2*(3x-2) = 38,  --->\r\n" );
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document.write( "4x + 2 + 6x - 4 = 38,\r\n" );
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document.write( "10x - 2 = 38  --->  10x = 38 + 2  --->  10x = 40  --->  x = 40/10 = 4.\r\n" );
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document.write( "Answer.  x = 4.\r\n" );
document.write( "         The length = 2x+1 = 9.  The width = 3x-2 = 10.\r\n" );
document.write( "         The width is longer than the length.\r\n" );
document.write( "         Author !?\r\n" );
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