document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91091>Question 91091</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you all could solve this one, I would be able to solve the rest that are like it and you would have my eternal adoration.\r<BR>\n" );
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document.write( "The diameter (in inches) of a a 80 foot long wire has that  a resistance of 24 ohms is defined by the function 24= 80/d2 (to the power of two that is). What is its diameter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66111 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter (in inches) of a a 80 foot long wire has that a resistance of 24 ohms is defined by the function 24= 80/d^2 (to the power of two that is). What is its diameter?<BR>\n" );
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document.write( "24= 80/d^2<BR>\n" );
document.write( "Multiply both sides by d^2; divide both sides by 24<BR>\n" );
document.write( "d^2 = 80/24<BR>\n" );
document.write( "Take the square root of both sides to get:<BR>\n" );
document.write( "d = 4sqrt(5)/2sqrt(6)<BR>\n" );
document.write( "d = 2sqrt(5)/sqrt6<BR>\n" );
document.write( "Multiply numerator and denominator by sqrt6 to get:<BR>\n" );
document.write( "d = 2sqrt30/6<BR>\n" );
document.write( "d = sqrt30/3<BR>\n" );
document.write( "d = (1/3) sqrt30<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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