document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045545>Question 1045545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> show in a new way that the points (-1 -2), (5 4), (-3 0) are the vertices of a right triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #661058 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=661058\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A vector associated with the points (-1,-2) and (5,4) is < 5--1, 4--2 > = < 6, 6 >.\r<BR>\n" );
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document.write( "A vector associated with the points (-1,-2) and (-3,0) is < -3--1,0--2 > = < -2,2 >.\r<BR>\n" );
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document.write( "Two vectors are perpendicular (or orthogonal) if their dot product is 0, \r<BR>\n" );
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document.write( "< 6,6 >*<-2,2 > = -12 + 12 = 0.\r<BR>\n" );
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document.write( "This, however, is not a new way, just a little level higher.  \r<BR>\n" );
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document.write( "Another way of showing this perpendicularity, but still not a \"new\" way, just a level lower, is <BR>\n" );
document.write( "getting the slope of the line passing through (-1,-2) and <BR>\n" );
document.write( "(5,4) and comparing this with the slope of the line passing through (-1,-2) <BR>\n" );
document.write( "and (-3,0). </SPAN>\n" );
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