document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045491>Question 1045491</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car travelled the first 240km at a certain speed and then the next 192km 8kph faster than its initial speed. What is its initial speed if the entire trip took 10 hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660971 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the initial speed. Then:<BR>\n" );
document.write( "240/n+192/(n+8)=10<BR>\n" );
document.write( "240(n+8)+192n=10(nē+8n)<BR>\n" );
document.write( "432n+1920=10nē+80n<BR>\n" );
document.write( "10nē-352n-1920=0<BR>\n" );
document.write( "5nē-176n-960=0<BR>\n" );
document.write( "(5n+24)(n-40)=0<BR>\n" );
document.write( "n=40,-24/5<BR>\n" );
document.write( "Throwing out the negative result, we get 40 kph as the original speed. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );