document.write( "Question 1045468: Due to inclement weather, the pilot of the plane slows down the plane's regular flying rate by 25%. This results an additional 1.5hours in covering 3000km distance to its regular time required for the trip. Find the regular rate of the trip \n" ); document.write( "

Algebra.Com's Answer #660933 by MathTherapy(10556) $\"\"$ $\"About$

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Due to inclement weather, the pilot of the plane slows down the plane's regular flying rate by 25%. This results an additional 1.5hours in covering 3000km distance to its regular time required for the trip. Find the regular rate of the trip
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Let regular rate be S
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document.write( "Then reduced rate during trip = .75S
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document.write( "Time to cover 3,000 km at regular rate: 
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document.write( "Time to cover 3,000 km at reduced rate: 
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document.write( "We then get the following TIME equation: 
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document.write( "3,000(.75) = 3,000 – 1.5(.75S) -------- Multiplying by LCD, .75S
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document.write( "2,250 = 3,000 – 1.125S
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document.write( "1.125S = 3,000 – 2,250
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document.write( "1.125S = 750
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document.write( "S, or regular rate =  = 
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document.write( "It is that SIMPLE, with just ONE (1) variable: the one you're looking for! \n" );
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