document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045104>Question 1045104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of one of two complementary angles is 6 degrees less than one half the measure of the other. Find the measure of the smaller angle.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660931 by </B><A HREF=/tutors/aboutme.mpl?userid=jhunjiro><B>jhunjiro(67)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jhunjiro><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jhunjiro><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x - larger angle<BR>\n" );
document.write( "y - smaller angle\r<BR>\n" );
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document.write( "complementary angle = 90 degrees\r<BR>\n" );
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document.write( "x + y = 90 (1st equation)\r<BR>\n" );
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document.write( "measure of one of two complementary angles means \"y\"<BR>\n" );
document.write( " is means \"equal\"<BR>\n" );
document.write( "6 degrees less than one half the measure of the other means  \".5x-6\"\r<BR>\n" );
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document.write( "y = .5x - 6 (2nd equation)\r<BR>\n" );
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document.write( "Using substitution method:\r<BR>\n" );
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document.write( "x + .5x - 6 = 90<BR>\n" );
document.write( "1.5x = 96\r<BR>\n" );
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document.write( "x = 64 degrees\r<BR>\n" );
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document.write( "y = .5(64)-6\r<BR>\n" );
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document.write( "y = 26 degrees (smaller angle)\r<BR>\n" );
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