document.write( "Question 1045455: Please help. I would like the answer in radians. Thanks!
\n" ); document.write( "2cos^2x + sinx -1 =0
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Algebra.Com's Answer #660909 by ikleyn(52847)\"\" \"About 
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\n" ); document.write( "Please help. I would like the answer in radians. Thanks!
\n" ); document.write( "2cos^2x + sinx -1 =0
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document.write( "First what we need to do is to reduce the given equation to the quadratic equation for sin(x).\r\n" );
document.write( "For it, use the identity cos^2(x) = 1-sin^2(x) and replace cos^2(x) in the equation by this expression. You will get\r\n" );
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document.write( "2*(1-sin^2(x) + sin(x) - 1 = 0,   or\r\n" );
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document.write( "2 - 2sin^2(x) + sin(x) - 1 = 0,   or\r\n" );
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document.write( "2sin^2(x) - sin(x) - 1 = 0.\r\n" );
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document.write( "Factor left side:\r\n" );
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document.write( "(2sin(x) + 1)*(sin(x) - 1) = 0.\r\n" );
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document.write( "Now the equation deploys in two independent equations:\r\n" );
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document.write( "1.  2sin(x) + 1 = 0  --->  sin(x) = \"-1%2F2\"  --->  x = \"7pi%2F6\"  and/or  x = \"11pi%2F6\".\r\n" );
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document.write( "2.  sin(x) - 1 = 0  --->  sin(x) = 1  --->  x = \"pi%2F2\".\r\n" );
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document.write( "Answer.  The solutions are  x = \"pi%2F2\",  \"7pi%2F6\" and  \"11pi%2F6\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Plot y = \"2cos%5E2%28x%29+%2B+sin%28x%29+-1\"\r
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