document.write( "Question 1045449: Explain me how to do this problem.
\n" ); document.write( "m < OZP = 4r+2, m < PZQ = 5r-12, and m < OZQ = 125.
\n" ); document.write( "What are m < OZP and m < PZQ?\r
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Algebra.Com's Answer #660900 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
angle OZP and angle PZQ combine to angle OZQ (this can be seen if you draw out the figure or use the figure given to you in the book)\r
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\n" ); document.write( "\n" ); document.write( "So this means\r
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\n" ); document.write( "\n" ); document.write( "(measure of angle OZP)+(measure of angle PZQ)=(measure of angle OZQ)\r
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\n" ); document.write( "\n" ); document.write( "(m < OZP)+(m < PZQ)=(m < OZQ)\r
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\n" ); document.write( "\n" ); document.write( "(4r+2)+(5r-12)=(125)\r
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\n" ); document.write( "\n" ); document.write( "4r+2+5r-12=125\r
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\n" ); document.write( "\n" ); document.write( "9r-10=125\r
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\n" ); document.write( "\n" ); document.write( "9r-10+10=125+10\r
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\n" ); document.write( "\n" ); document.write( "9r+0=135\r
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\n" ); document.write( "\n" ); document.write( "9r=135\r
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\n" ); document.write( "\n" ); document.write( "9r/9=135/9\r
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\n" ); document.write( "\n" ); document.write( "r = 15\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that the value of r is r = 15, we can use this to find the angles\r
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\n" ); document.write( "\n" ); document.write( "m < OZP = 4r+2
\n" ); document.write( "m < OZP = 4*15+2
\n" ); document.write( "m < OZP = 60+2
\n" ); document.write( "m < OZP = 62\r
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\n" ); document.write( "\n" ); document.write( "m < PZQ = 5r - 12
\n" ); document.write( "m < PZQ = 5*15 - 12
\n" ); document.write( "m < PZQ = 75 - 12
\n" ); document.write( "m < PZQ = 63\r
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\n" ); document.write( "\n" ); document.write( "Summary:
\n" ); document.write( "m < OZP = 62
\n" ); document.write( "m < PZQ = 63
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