document.write( "Question 1045447: The answer must be given In radians. Thanks!
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document.write( "2cos^2x + 3cosx -2 = 0 \n" );
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Algebra.Com's Answer #660884 by stanbon(75887) ![]() You can put this solution on YOUR website! The answer must be given In radians. Thanks! \n" ); document.write( "2cos^2x + 3cosx -2 = 0 \n" ); document.write( "---- \n" ); document.write( "Factor:: \n" ); document.write( "(2cos(x)-1)(cos(x)+2) = 0 \n" ); document.write( "------ \n" ); document.write( "cos(x) = 1/2 or cos(x) = -2 (extraneous) \n" ); document.write( "----- \n" ); document.write( "x = arccos(1/2) = pi/3 or x = (11/3)pi \n" ); document.write( "---------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------- \n" ); document.write( " |