document.write( "Question 1045447: The answer must be given In radians. Thanks!
\n" ); document.write( "2cos^2x + 3cosx -2 = 0
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Algebra.Com's Answer #660884 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The answer must be given In radians. Thanks!
\n" ); document.write( "2cos^2x + 3cosx -2 = 0
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\n" ); document.write( "Factor::
\n" ); document.write( "(2cos(x)-1)(cos(x)+2) = 0
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\n" ); document.write( "cos(x) = 1/2 or cos(x) = -2 (extraneous)
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\n" ); document.write( "x = arccos(1/2) = pi/3 or x = (11/3)pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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