document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045313>Question 1045313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I give an example of a binomial in the form a&#8730;b + c&#8730;d and then multiply bytheir conjugate? How do I find their products?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660741 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 sqrt (3)+4 sqrt(5)<BR>\n" );
document.write( "conjugate is <BR>\n" );
document.write( "2 sqrt(3)-4 sqrt(5)<BR>\n" );
document.write( "Product is<BR>\n" );
document.write( "4*3-8 sqrt (15)+8 sqrt (12)-80=-68-8 sqrt(15)+16 sqrt (3)<BR>\n" );
document.write( "The first term squares 2 sqrt(3), which is 4*3<BR>\n" );
document.write( "The internal products are written, and 8 sqrt(12)=16 sqrt (3), because sqrt (12)=2 sqrt(3)<BR>\n" );
document.write( "The last product is minus 16*5<BR>\n" );
document.write( "The conjugate is the same binomials subtracted (or added), so that the first and last radical terms are eliminated. </SPAN>\n" );
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