document.write( "Question 1045324: If 2016 = 2^x*3^y*5^z*7^u are non negative integers, the value of x+y+2016z+3u will be a)10 b)11 c)12 d)13 \n" ); document.write( "

Algebra.Com's Answer #660724 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "If 2016 = 2^x*3^y*5^z*7^u are non negative integers, the value of x+y+2016z+3u will be a)10 b)11 c)12 d)13
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document.write( "2016 = .\r\n" );
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document.write( "Therefore,  If 2016 = 2^x*3^y*5^z*7^u, then x = 5, y = 2, z = 0 and u = 1.\r\n" );
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document.write( "Having this, you will easily find x + y + 2016z + 3u = 5 + 2 + 2016*0 + 3*1 = 10\r\n" );
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