document.write( "Question 1045306: I am a little confused over this so please help me solving it
\n" ); document.write( "\"a%5Ep=b%5Eq=c%5Er=d%5Es\" and ab=cd then the value of \"1%2Fp%2B1%2Fq-1%2Fr-1%2Fs\" reduces to?
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Algebra.Com's Answer #660706 by KMST(5328)\"\" \"About 
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The expression \"1%2Fp%2B1%2Fq-1%2Fr-1%2Fs\" will be undefined if one or more of those denominators is zero.
\n" ); document.write( "If nothing was specified about the exponents,
\n" ); document.write( "we have to consider the case that one (or more) of them is zero:
\n" ); document.write( "If \"pqrs=0\" , then \"1%2Fp%2B1%2Fq-1%2Fr-1%2Fs\" is undefined.\r
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\n" ); document.write( "\n" ); document.write( "If \"pqrs%3C%3E0\" , then \"1%2Fp%2B1%2Fq-1%2Fr-1%2Fs=highlight%280%29\" :
\n" ); document.write( "Looking at just \"c%5Er=d%5Es\" , we can write
\n" ); document.write( "\"c%5Er=d%5Es\" ---> \"%28c%5Er%29%5E%281%2Fr%29=%28d%5Es%29%5E%281%2Fr%29\" ---> \"c%5E%22r%2Fr%22=d%5E%22s%2Fr%22\" ---> \"c=d%5E%22s%2Fr%22\" .
\n" ); document.write( "Since \"a%5Ep=d%5Es\" and \"b%5Eq=d%5Es\" ,
\n" ); document.write( "we can also write \"a\" and \"b\" as powers of \"d\" :
\n" ); document.write( "\"a=d%5E%22s%2Fp%22\" and \"b=d%5E%22s%2Fq%22\" .
\n" ); document.write( "Substituting the expressions found for \"a\" , \"b\" , and \"c\" into \"ab=cd\" , we get to the solution.
\n" ); document.write( "\"a%2Ab=c%2Ad\" --> \"d%5E%22s%2Fp%22%2Ad%5E%22s%2Fq%22=d%5E%22s%2Fr%22%2Ad\" --> \"d%5E%22s%2Fp%22%2Ad%5E%22s%2Fq%22=d%5E%22s%2Fr%22%2Ad\" --> \"d%5E%28%22s%2Fp%22%2B%22s%2Fq%22%29=d%5E%28%22s%2Fr%22%2B1%29\" --> \"s%2Fp%2Bs%2Fq=r%2Fs%2B1\"
\n" ); document.write( "And multiplkying both sides of the last equation above times \"1%2Fs\" , we get
\n" ); document.write( "\"1%2Fp%2B1%2Fq=1%2Fr%2B1%2Fs\" .
\n" ); document.write( "So, subtracting \"1%2Fr%2B1%2Fs\" from both sides, we get
\n" ); document.write( "\"1%2Fp%2B1%2Fq-%281%2Fr%2B1%2Fs%29=1%2Fr%2B1%2Fs-%281%2Fr%2B1%2Fs%29\" --> \"1%2Fp%2B1%2Fq-1%2Fr-1%2Fs=1%2Fr%2B1%2Fs-1%2Fr-1%2Fs\" --> \"highlight%281%2Fp%2B1%2Fq-1%2Fr-1%2Fs=0%29\" .
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