document.write( "Question 1045280: The annual interest on a $9000 investment exceeds the interest earned on an $8000 investment by $47. The $9000 is invested at a 0.3% higher rate of interest than the $8000. What is the interest rate of each investment? \n" ); document.write( "
Algebra.Com's Answer #660696 by advanced_Learner(501)![]() ![]() You can put this solution on YOUR website! 9000a-8000b=47 \n" ); document.write( "(a)-b=0.3% \n" ); document.write( "can you solve from now on....... \n" ); document.write( " |