document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045214>Question 1045214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The age of a father is 5 more the age of 6 times the age of his son. 7 years after, the age of the father becomes 3 more than the age of son. Find their present ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660684 by </B><A HREF=/tutors/aboutme.mpl?userid=advanced_Learner><B>advanced_Learner(501)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=advanced_Learner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=advanced_Learner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The age of a father is 5 more the age of 6 times the age of his son. 7 years after, the age of the father becomes 3 times the age of son. Find their present ages?\r<BR>\n" );
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document.write( "let x be son age<BR>\n" );
document.write( "father age is     6x+5\r<BR>\n" );
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document.write( "after 7 years\r<BR>\n" );
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document.write( "x+7<BR>\n" );
document.write( "6x+12\r<BR>\n" );
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document.write( "6x+12=(x+7)*3<BR>\n" );
document.write( "x=3\r<BR>\n" );
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document.write( "3       23<BR>\n" );
document.write( "10       30<BR>\n" );
document.write( "indeed 30=3*10 </SPAN>\n" );
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