document.write( "Question 1045232: Please help solve this. Detailed workings is very much appreciated, thanks.
\n" ); document.write( "The function of f is given by: f(x)= (2x-3)^2
\n" ); document.write( "The graph of f(x) has the shape of a parabola. Find the coordinates of its vertex.
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Algebra.Com's Answer #660628 by Boreal(15235)\"\" \"About 
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Foil out the function
\n" ); document.write( "(2x-3)^2=4x^2-12x+9, just the way (a+b)^2=a^2+2ab+b^2
\n" ); document.write( "The vertex x point is at -b/2a or -(-12)/8=12/8 , or 1.5; a is 4, b is -12, and c is 9.
\n" ); document.write( "Go back to the original function
\n" ); document.write( "(2x-3)^2=(3-3)^2=0.
\n" ); document.write( "the vertex is at (1.5, 0)
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%282x-3%29%5E2%29\"
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