document.write( "Question 1045132: In a vehicle front wheel is 4m in circumference and rear wheel is 6m in circumference, After traveling few distance front wheel rotated 10 times than rear wheel. What is the distance traveled by the vehicle? (please explain the method) \n" ); document.write( "
Algebra.Com's Answer #660568 by KMST(5328)\"\" \"About 
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\"n\"= number of turns for the rear wheel
\n" ); document.write( "Since the front wheel rotated 10 times more than the rear wheel,
\n" ); document.write( "\"n%2B10\"= number of turns for the front wheel.
\n" ); document.write( "Since the circumference of the rear wheel, in meters, is \"6\" ,
\n" ); document.write( "each turn of the rear wheel makes the vehicle advance \"6\" meters.
\n" ); document.write( "So, \"6n\"= distance traveled by the vehicle, in meters.
\n" ); document.write( "Similarly, each turn of the from wheel corresponds to \"4\" meters of distance traveled.
\n" ); document.write( "So, we can also say that
\n" ); document.write( "\"4%28n%2B10%29\"= distance traveled by the vehicle, in meters.
\n" ); document.write( "Because we are talking about the same distance
\n" ); document.write( "\"6n=4%28n%2B10%29\" .
\n" ); document.write( "We just havwe to solve that equation to find \"n\" ,
\n" ); document.write( "and then we can calculate \"6n\"= distance traveled by the vehicle, in meters.
\n" ); document.write( "To verify that we solved teh problem correctly, we can also calculate
\n" ); document.write( "\"4%28n%2B10%29\"= distance traveled by the vehicle, in meters,
\n" ); document.write( "and it should be the same distance.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"6n=4%28n%2B10%29\"
\n" ); document.write( "\"6n=4n%2B40%29\"
\n" ); document.write( "\"6n-4n=40%29\"
\n" ); document.write( "\"2n=40%29\"
\n" ); document.write( "\"n=40%2F2\"
\n" ); document.write( "\"n=20\"
\n" ); document.write( "So, the rear wheel turned \"20\" times,
\n" ); document.write( "and the distance traveled by the vehicle, in meters, is
\n" ); document.write( "\"6%2A20=highlight%28120%29\" .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Verification:
\n" ); document.write( "If the rear wheel turned \"20\" times,
\n" ); document.write( "the front wheel must have turned \"20%2B10=30\" times.
\n" ); document.write( "with each turn of the front wheel corresponding to the vehicle advancing \"4\" meters,
\n" ); document.write( "\"30\" turns of the front wheel correspond to a distance traveled by the vehicle, in meters, of
\n" ); document.write( "\"4%2A30=120\" .
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