document.write( "Question 1043663: if log(a+b+c)=loga+logb+logc then prove that log(2a/1-a^2 + 2b/1-b^2 + 2c/1-c^2)= log 2a/1-a^2 + log 2b/1-b^2 + log 2c/1-c^2 \n" ); document.write( "
Algebra.Com's Answer #660462 by robertb(5830)![]() ![]() You can put this solution on YOUR website! We wish to show that \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the result to have meaning, it must be that 0 < a,b,c < 1, which can be determined by solving the inequalities \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "With this in mind, it is enough to show that \r \n" ); document.write( "\n" ); document.write( "a+b+c = abc ===> \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now on to the proof:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "<===> \n" ); document.write( "\n" ); document.write( "<===> \n" ); document.write( "\n" ); document.write( "Since a+b+c = abc, we get \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===> \n" ); document.write( "\n" ); document.write( "<===> \n" ); document.write( "\n" ); document.write( "<===> \n" ); document.write( "\n" ); document.write( "<===> \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And that's it...\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |