document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1045007>Question 1045007</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a slandered-sized rectangular rug is 40 ft. The length is 2 ft longer than the width. Find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660429 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2L+2W (1)<BR>\n" );
document.write( "and the problem says that:<BR>\n" );
document.write( "L = W+2 (2) Substitute in (1)<BR>\n" );
document.write( "2(W+2)+2W = 40<BR>\n" );
document.write( "2W+4+2W = 40<BR>\n" );
document.write( "4W = 36<BR>\n" );
document.write( "W = 9 This is the width, and the length is 9+2 = 11<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2(11)+2(9) = 40<BR>\n" );
document.write( "22+18 = 40 Correct<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );