document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1044952>Question 1044952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much clay do you need to add to 4 cubic yards of soil with 40% clay in order to make a soil with 60% clay? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #660389 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=660389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=amount of clay<BR>\n" );
document.write( "(4)(0.40)+x=(4+x)(0.60), the amount of pure clay in 4 yds^3 at 40% is 1.6 yds^3.  We add x amount of pure 100% clay<BR>\n" );
document.write( "1.6+x=2.4+0.60x<BR>\n" );
document.write( "-0.8=-0.4x<BR>\n" );
document.write( "x=2 yds^3 ANSWER<BR>\n" );
document.write( "check<BR>\n" );
document.write( "2/3 is 40%, 1/3 is 100%<BR>\n" );
document.write( "40+40+100 all divided by 3 is 60 </SPAN>\n" );
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